3.1.19 \(\int x^4 (d+c^2 d x^2)^3 (a+b \sinh ^{-1}(c x)) \, dx\) [19]

Optimal. Leaf size=226 \[ -\frac {16 b d^3 \sqrt {1+c^2 x^2}}{1155 c^5}-\frac {8 b d^3 \left (1+c^2 x^2\right )^{3/2}}{3465 c^5}-\frac {2 b d^3 \left (1+c^2 x^2\right )^{5/2}}{1925 c^5}-\frac {b d^3 \left (1+c^2 x^2\right )^{7/2}}{1617 c^5}+\frac {4 b d^3 \left (1+c^2 x^2\right )^{9/2}}{297 c^5}-\frac {b d^3 \left (1+c^2 x^2\right )^{11/2}}{121 c^5}+\frac {1}{5} d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{7} c^2 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{3} c^4 d^3 x^9 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{11} c^6 d^3 x^{11} \left (a+b \sinh ^{-1}(c x)\right ) \]

[Out]

-8/3465*b*d^3*(c^2*x^2+1)^(3/2)/c^5-2/1925*b*d^3*(c^2*x^2+1)^(5/2)/c^5-1/1617*b*d^3*(c^2*x^2+1)^(7/2)/c^5+4/29
7*b*d^3*(c^2*x^2+1)^(9/2)/c^5-1/121*b*d^3*(c^2*x^2+1)^(11/2)/c^5+1/5*d^3*x^5*(a+b*arcsinh(c*x))+3/7*c^2*d^3*x^
7*(a+b*arcsinh(c*x))+1/3*c^4*d^3*x^9*(a+b*arcsinh(c*x))+1/11*c^6*d^3*x^11*(a+b*arcsinh(c*x))-16/1155*b*d^3*(c^
2*x^2+1)^(1/2)/c^5

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Rubi [A]
time = 0.19, antiderivative size = 226, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {276, 5803, 12, 1813, 1634} \begin {gather*} \frac {1}{11} c^6 d^3 x^{11} \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{3} c^4 d^3 x^9 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{7} c^2 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{5} d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )-\frac {b d^3 \left (c^2 x^2+1\right )^{11/2}}{121 c^5}+\frac {4 b d^3 \left (c^2 x^2+1\right )^{9/2}}{297 c^5}-\frac {b d^3 \left (c^2 x^2+1\right )^{7/2}}{1617 c^5}-\frac {2 b d^3 \left (c^2 x^2+1\right )^{5/2}}{1925 c^5}-\frac {8 b d^3 \left (c^2 x^2+1\right )^{3/2}}{3465 c^5}-\frac {16 b d^3 \sqrt {c^2 x^2+1}}{1155 c^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x^4*(d + c^2*d*x^2)^3*(a + b*ArcSinh[c*x]),x]

[Out]

(-16*b*d^3*Sqrt[1 + c^2*x^2])/(1155*c^5) - (8*b*d^3*(1 + c^2*x^2)^(3/2))/(3465*c^5) - (2*b*d^3*(1 + c^2*x^2)^(
5/2))/(1925*c^5) - (b*d^3*(1 + c^2*x^2)^(7/2))/(1617*c^5) + (4*b*d^3*(1 + c^2*x^2)^(9/2))/(297*c^5) - (b*d^3*(
1 + c^2*x^2)^(11/2))/(121*c^5) + (d^3*x^5*(a + b*ArcSinh[c*x]))/5 + (3*c^2*d^3*x^7*(a + b*ArcSinh[c*x]))/7 + (
c^4*d^3*x^9*(a + b*ArcSinh[c*x]))/3 + (c^6*d^3*x^11*(a + b*ArcSinh[c*x]))/11

Rule 12

Int[(a_)*(u_), x_Symbol] :> Dist[a, Int[u, x], x] /; FreeQ[a, x] &&  !MatchQ[u, (b_)*(v_) /; FreeQ[b, x]]

Rule 276

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*(a + b*x^n)^p,
x], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0]

Rule 1634

Int[(Px_)*((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[Px*(a + b*x)
^m*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, m, n}, x] && PolyQ[Px, x] && (IntegersQ[m, n] || IGtQ[m, -2]) &&
GtQ[Expon[Px, x], 2]

Rule 1813

Int[(Pq_)*(x_)^(m_.)*((a_) + (b_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[1/2, Subst[Int[x^((m - 1)/2)*SubstFor[x^2,
Pq, x]*(a + b*x)^p, x], x, x^2], x] /; FreeQ[{a, b, p}, x] && PolyQ[Pq, x^2] && IntegerQ[(m - 1)/2]

Rule 5803

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))*((f_.)*(x_))^(m_)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> With[{u =
IntHide[(f*x)^m*(d + e*x^2)^p, x]}, Dist[a + b*ArcSinh[c*x], u, x] - Dist[b*c, Int[SimplifyIntegrand[u/Sqrt[1
+ c^2*x^2], x], x], x]] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[e, c^2*d] && IGtQ[p, 0]

Rubi steps

\begin {align*} \int x^4 \left (d+c^2 d x^2\right )^3 \left (a+b \sinh ^{-1}(c x)\right ) \, dx &=\frac {1}{5} d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{7} c^2 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{3} c^4 d^3 x^9 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{11} c^6 d^3 x^{11} \left (a+b \sinh ^{-1}(c x)\right )-(b c) \int \frac {d^3 x^5 \left (231+495 c^2 x^2+385 c^4 x^4+105 c^6 x^6\right )}{1155 \sqrt {1+c^2 x^2}} \, dx\\ &=\frac {1}{5} d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{7} c^2 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{3} c^4 d^3 x^9 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{11} c^6 d^3 x^{11} \left (a+b \sinh ^{-1}(c x)\right )-\frac {\left (b c d^3\right ) \int \frac {x^5 \left (231+495 c^2 x^2+385 c^4 x^4+105 c^6 x^6\right )}{\sqrt {1+c^2 x^2}} \, dx}{1155}\\ &=\frac {1}{5} d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{7} c^2 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{3} c^4 d^3 x^9 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{11} c^6 d^3 x^{11} \left (a+b \sinh ^{-1}(c x)\right )-\frac {\left (b c d^3\right ) \text {Subst}\left (\int \frac {x^2 \left (231+495 c^2 x+385 c^4 x^2+105 c^6 x^3\right )}{\sqrt {1+c^2 x}} \, dx,x,x^2\right )}{2310}\\ &=\frac {1}{5} d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{7} c^2 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{3} c^4 d^3 x^9 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{11} c^6 d^3 x^{11} \left (a+b \sinh ^{-1}(c x)\right )-\frac {\left (b c d^3\right ) \text {Subst}\left (\int \left (\frac {16}{c^4 \sqrt {1+c^2 x}}+\frac {8 \sqrt {1+c^2 x}}{c^4}+\frac {6 \left (1+c^2 x\right )^{3/2}}{c^4}+\frac {5 \left (1+c^2 x\right )^{5/2}}{c^4}-\frac {140 \left (1+c^2 x\right )^{7/2}}{c^4}+\frac {105 \left (1+c^2 x\right )^{9/2}}{c^4}\right ) \, dx,x,x^2\right )}{2310}\\ &=-\frac {16 b d^3 \sqrt {1+c^2 x^2}}{1155 c^5}-\frac {8 b d^3 \left (1+c^2 x^2\right )^{3/2}}{3465 c^5}-\frac {2 b d^3 \left (1+c^2 x^2\right )^{5/2}}{1925 c^5}-\frac {b d^3 \left (1+c^2 x^2\right )^{7/2}}{1617 c^5}+\frac {4 b d^3 \left (1+c^2 x^2\right )^{9/2}}{297 c^5}-\frac {b d^3 \left (1+c^2 x^2\right )^{11/2}}{121 c^5}+\frac {1}{5} d^3 x^5 \left (a+b \sinh ^{-1}(c x)\right )+\frac {3}{7} c^2 d^3 x^7 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{3} c^4 d^3 x^9 \left (a+b \sinh ^{-1}(c x)\right )+\frac {1}{11} c^6 d^3 x^{11} \left (a+b \sinh ^{-1}(c x)\right )\\ \end {align*}

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Mathematica [A]
time = 0.08, size = 143, normalized size = 0.63 \begin {gather*} \frac {d^3 \left (3465 a c^5 x^5 \left (231+495 c^2 x^2+385 c^4 x^4+105 c^6 x^6\right )-b \sqrt {1+c^2 x^2} \left (50488-25244 c^2 x^2+18933 c^4 x^4+117625 c^6 x^6+111475 c^8 x^8+33075 c^{10} x^{10}\right )+3465 b c^5 x^5 \left (231+495 c^2 x^2+385 c^4 x^4+105 c^6 x^6\right ) \sinh ^{-1}(c x)\right )}{4002075 c^5} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x^4*(d + c^2*d*x^2)^3*(a + b*ArcSinh[c*x]),x]

[Out]

(d^3*(3465*a*c^5*x^5*(231 + 495*c^2*x^2 + 385*c^4*x^4 + 105*c^6*x^6) - b*Sqrt[1 + c^2*x^2]*(50488 - 25244*c^2*
x^2 + 18933*c^4*x^4 + 117625*c^6*x^6 + 111475*c^8*x^8 + 33075*c^10*x^10) + 3465*b*c^5*x^5*(231 + 495*c^2*x^2 +
385*c^4*x^4 + 105*c^6*x^6)*ArcSinh[c*x]))/(4002075*c^5)

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Maple [A]
time = 1.01, size = 206, normalized size = 0.91

method	result	size
derivativedivides	\(\frac {d^{3} a \left (\frac {1}{11} c^{11} x^{11}+\frac {1}{3} c^{9} x^{9}+\frac {3}{7} c^{7} x^{7}+\frac {1}{5} c^{5} x^{5}\right )+d^{3} b \left (\frac {\arcsinh \left (c x \right ) c^{11} x^{11}}{11}+\frac {\arcsinh \left (c x \right ) c^{9} x^{9}}{3}+\frac {3 \arcsinh \left (c x \right ) c^{7} x^{7}}{7}+\frac {\arcsinh \left (c x \right ) c^{5} x^{5}}{5}-\frac {c^{10} x^{10} \sqrt {c^{2} x^{2}+1}}{121}-\frac {91 c^{8} x^{8} \sqrt {c^{2} x^{2}+1}}{3267}-\frac {4705 c^{6} x^{6} \sqrt {c^{2} x^{2}+1}}{160083}-\frac {6311 c^{4} x^{4} \sqrt {c^{2} x^{2}+1}}{1334025}+\frac {25244 c^{2} x^{2} \sqrt {c^{2} x^{2}+1}}{4002075}-\frac {50488 \sqrt {c^{2} x^{2}+1}}{4002075}\right )}{c^{5}}\)	\(206\)
default	\(\frac {d^{3} a \left (\frac {1}{11} c^{11} x^{11}+\frac {1}{3} c^{9} x^{9}+\frac {3}{7} c^{7} x^{7}+\frac {1}{5} c^{5} x^{5}\right )+d^{3} b \left (\frac {\arcsinh \left (c x \right ) c^{11} x^{11}}{11}+\frac {\arcsinh \left (c x \right ) c^{9} x^{9}}{3}+\frac {3 \arcsinh \left (c x \right ) c^{7} x^{7}}{7}+\frac {\arcsinh \left (c x \right ) c^{5} x^{5}}{5}-\frac {c^{10} x^{10} \sqrt {c^{2} x^{2}+1}}{121}-\frac {91 c^{8} x^{8} \sqrt {c^{2} x^{2}+1}}{3267}-\frac {4705 c^{6} x^{6} \sqrt {c^{2} x^{2}+1}}{160083}-\frac {6311 c^{4} x^{4} \sqrt {c^{2} x^{2}+1}}{1334025}+\frac {25244 c^{2} x^{2} \sqrt {c^{2} x^{2}+1}}{4002075}-\frac {50488 \sqrt {c^{2} x^{2}+1}}{4002075}\right )}{c^{5}}\)	\(206\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*(c^2*d*x^2+d)^3*(a+b*arcsinh(c*x)),x,method=_RETURNVERBOSE)

[Out]

1/c^5*(d^3*a*(1/11*c^11*x^11+1/3*c^9*x^9+3/7*c^7*x^7+1/5*c^5*x^5)+d^3*b*(1/11*arcsinh(c*x)*c^11*x^11+1/3*arcsi
nh(c*x)*c^9*x^9+3/7*arcsinh(c*x)*c^7*x^7+1/5*arcsinh(c*x)*c^5*x^5-1/121*c^10*x^10*(c^2*x^2+1)^(1/2)-91/3267*c^
8*x^8*(c^2*x^2+1)^(1/2)-4705/160083*c^6*x^6*(c^2*x^2+1)^(1/2)-6311/1334025*c^4*x^4*(c^2*x^2+1)^(1/2)+25244/400
2075*c^2*x^2*(c^2*x^2+1)^(1/2)-50488/4002075*(c^2*x^2+1)^(1/2)))

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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 465 vs. \(2 (194) = 388\).
time = 0.27, size = 465, normalized size = 2.06 \begin {gather*} \frac {1}{11} \, a c^{6} d^{3} x^{11} + \frac {1}{3} \, a c^{4} d^{3} x^{9} + \frac {3}{7} \, a c^{2} d^{3} x^{7} + \frac {1}{7623} \, {\left (693 \, x^{11} \operatorname {arsinh}\left (c x\right ) - {\left (\frac {63 \, \sqrt {c^{2} x^{2} + 1} x^{10}}{c^{2}} - \frac {70 \, \sqrt {c^{2} x^{2} + 1} x^{8}}{c^{4}} + \frac {80 \, \sqrt {c^{2} x^{2} + 1} x^{6}}{c^{6}} - \frac {96 \, \sqrt {c^{2} x^{2} + 1} x^{4}}{c^{8}} + \frac {128 \, \sqrt {c^{2} x^{2} + 1} x^{2}}{c^{10}} - \frac {256 \, \sqrt {c^{2} x^{2} + 1}}{c^{12}}\right )} c\right )} b c^{6} d^{3} + \frac {1}{945} \, {\left (315 \, x^{9} \operatorname {arsinh}\left (c x\right ) - {\left (\frac {35 \, \sqrt {c^{2} x^{2} + 1} x^{8}}{c^{2}} - \frac {40 \, \sqrt {c^{2} x^{2} + 1} x^{6}}{c^{4}} + \frac {48 \, \sqrt {c^{2} x^{2} + 1} x^{4}}{c^{6}} - \frac {64 \, \sqrt {c^{2} x^{2} + 1} x^{2}}{c^{8}} + \frac {128 \, \sqrt {c^{2} x^{2} + 1}}{c^{10}}\right )} c\right )} b c^{4} d^{3} + \frac {1}{5} \, a d^{3} x^{5} + \frac {3}{245} \, {\left (35 \, x^{7} \operatorname {arsinh}\left (c x\right ) - {\left (\frac {5 \, \sqrt {c^{2} x^{2} + 1} x^{6}}{c^{2}} - \frac {6 \, \sqrt {c^{2} x^{2} + 1} x^{4}}{c^{4}} + \frac {8 \, \sqrt {c^{2} x^{2} + 1} x^{2}}{c^{6}} - \frac {16 \, \sqrt {c^{2} x^{2} + 1}}{c^{8}}\right )} c\right )} b c^{2} d^{3} + \frac {1}{75} \, {\left (15 \, x^{5} \operatorname {arsinh}\left (c x\right ) - {\left (\frac {3 \, \sqrt {c^{2} x^{2} + 1} x^{4}}{c^{2}} - \frac {4 \, \sqrt {c^{2} x^{2} + 1} x^{2}}{c^{4}} + \frac {8 \, \sqrt {c^{2} x^{2} + 1}}{c^{6}}\right )} c\right )} b d^{3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(c^2*d*x^2+d)^3*(a+b*arcsinh(c*x)),x, algorithm="maxima")

[Out]

1/11*a*c^6*d^3*x^11 + 1/3*a*c^4*d^3*x^9 + 3/7*a*c^2*d^3*x^7 + 1/7623*(693*x^11*arcsinh(c*x) - (63*sqrt(c^2*x^2
+ 1)*x^10/c^2 - 70*sqrt(c^2*x^2 + 1)*x^8/c^4 + 80*sqrt(c^2*x^2 + 1)*x^6/c^6 - 96*sqrt(c^2*x^2 + 1)*x^4/c^8 +
128*sqrt(c^2*x^2 + 1)*x^2/c^10 - 256*sqrt(c^2*x^2 + 1)/c^12)*c)*b*c^6*d^3 + 1/945*(315*x^9*arcsinh(c*x) - (35*
sqrt(c^2*x^2 + 1)*x^8/c^2 - 40*sqrt(c^2*x^2 + 1)*x^6/c^4 + 48*sqrt(c^2*x^2 + 1)*x^4/c^6 - 64*sqrt(c^2*x^2 + 1)
*x^2/c^8 + 128*sqrt(c^2*x^2 + 1)/c^10)*c)*b*c^4*d^3 + 1/5*a*d^3*x^5 + 3/245*(35*x^7*arcsinh(c*x) - (5*sqrt(c^2
*x^2 + 1)*x^6/c^2 - 6*sqrt(c^2*x^2 + 1)*x^4/c^4 + 8*sqrt(c^2*x^2 + 1)*x^2/c^6 - 16*sqrt(c^2*x^2 + 1)/c^8)*c)*b
*c^2*d^3 + 1/75*(15*x^5*arcsinh(c*x) - (3*sqrt(c^2*x^2 + 1)*x^4/c^2 - 4*sqrt(c^2*x^2 + 1)*x^2/c^4 + 8*sqrt(c^2
*x^2 + 1)/c^6)*c)*b*d^3

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Fricas [A]
time = 0.35, size = 201, normalized size = 0.89 \begin {gather*} \frac {363825 \, a c^{11} d^{3} x^{11} + 1334025 \, a c^{9} d^{3} x^{9} + 1715175 \, a c^{7} d^{3} x^{7} + 800415 \, a c^{5} d^{3} x^{5} + 3465 \, {\left (105 \, b c^{11} d^{3} x^{11} + 385 \, b c^{9} d^{3} x^{9} + 495 \, b c^{7} d^{3} x^{7} + 231 \, b c^{5} d^{3} x^{5}\right )} \log \left (c x + \sqrt {c^{2} x^{2} + 1}\right ) - {\left (33075 \, b c^{10} d^{3} x^{10} + 111475 \, b c^{8} d^{3} x^{8} + 117625 \, b c^{6} d^{3} x^{6} + 18933 \, b c^{4} d^{3} x^{4} - 25244 \, b c^{2} d^{3} x^{2} + 50488 \, b d^{3}\right )} \sqrt {c^{2} x^{2} + 1}}{4002075 \, c^{5}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(c^2*d*x^2+d)^3*(a+b*arcsinh(c*x)),x, algorithm="fricas")

[Out]

1/4002075*(363825*a*c^11*d^3*x^11 + 1334025*a*c^9*d^3*x^9 + 1715175*a*c^7*d^3*x^7 + 800415*a*c^5*d^3*x^5 + 346
5*(105*b*c^11*d^3*x^11 + 385*b*c^9*d^3*x^9 + 495*b*c^7*d^3*x^7 + 231*b*c^5*d^3*x^5)*log(c*x + sqrt(c^2*x^2 + 1
)) - (33075*b*c^10*d^3*x^10 + 111475*b*c^8*d^3*x^8 + 117625*b*c^6*d^3*x^6 + 18933*b*c^4*d^3*x^4 - 25244*b*c^2*
d^3*x^2 + 50488*b*d^3)*sqrt(c^2*x^2 + 1))/c^5

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Sympy [A]
time = 3.25, size = 289, normalized size = 1.28 \begin {gather*} \begin {cases} \frac {a c^{6} d^{3} x^{11}}{11} + \frac {a c^{4} d^{3} x^{9}}{3} + \frac {3 a c^{2} d^{3} x^{7}}{7} + \frac {a d^{3} x^{5}}{5} + \frac {b c^{6} d^{3} x^{11} \operatorname {asinh}{\left (c x \right )}}{11} - \frac {b c^{5} d^{3} x^{10} \sqrt {c^{2} x^{2} + 1}}{121} + \frac {b c^{4} d^{3} x^{9} \operatorname {asinh}{\left (c x \right )}}{3} - \frac {91 b c^{3} d^{3} x^{8} \sqrt {c^{2} x^{2} + 1}}{3267} + \frac {3 b c^{2} d^{3} x^{7} \operatorname {asinh}{\left (c x \right )}}{7} - \frac {4705 b c d^{3} x^{6} \sqrt {c^{2} x^{2} + 1}}{160083} + \frac {b d^{3} x^{5} \operatorname {asinh}{\left (c x \right )}}{5} - \frac {6311 b d^{3} x^{4} \sqrt {c^{2} x^{2} + 1}}{1334025 c} + \frac {25244 b d^{3} x^{2} \sqrt {c^{2} x^{2} + 1}}{4002075 c^{3}} - \frac {50488 b d^{3} \sqrt {c^{2} x^{2} + 1}}{4002075 c^{5}} & \text {for}\: c \neq 0 \\\frac {a d^{3} x^{5}}{5} & \text {otherwise} \end {cases} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**4*(c**2*d*x**2+d)**3*(a+b*asinh(c*x)),x)

[Out]

Piecewise((a*c**6*d**3*x**11/11 + a*c**4*d**3*x**9/3 + 3*a*c**2*d**3*x**7/7 + a*d**3*x**5/5 + b*c**6*d**3*x**1
1*asinh(c*x)/11 - b*c**5*d**3*x**10*sqrt(c**2*x**2 + 1)/121 + b*c**4*d**3*x**9*asinh(c*x)/3 - 91*b*c**3*d**3*x
**8*sqrt(c**2*x**2 + 1)/3267 + 3*b*c**2*d**3*x**7*asinh(c*x)/7 - 4705*b*c*d**3*x**6*sqrt(c**2*x**2 + 1)/160083
+ b*d**3*x**5*asinh(c*x)/5 - 6311*b*d**3*x**4*sqrt(c**2*x**2 + 1)/(1334025*c) + 25244*b*d**3*x**2*sqrt(c**2*x
**2 + 1)/(4002075*c**3) - 50488*b*d**3*sqrt(c**2*x**2 + 1)/(4002075*c**5), Ne(c, 0)), (a*d**3*x**5/5, True))

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Giac [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(c^2*d*x^2+d)^3*(a+b*arcsinh(c*x)),x, algorithm="giac")

[Out]

Exception raised: RuntimeError >> An error occurred running a Giac command:INPUT:sage2OUTPUT:sym2poly/r2sym(co
nst gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int x^4\,\left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )\,{\left (d\,c^2\,x^2+d\right )}^3 \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*(a + b*asinh(c*x))*(d + c^2*d*x^2)^3,x)

[Out]

int(x^4*(a + b*asinh(c*x))*(d + c^2*d*x^2)^3, x)

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